If three numbers are in ap whose sum is 21 and product is 336.find the number
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let numbers be a-d , a, a+d
3a = 21 , a = 7
7(49²-d²) = 336 , 48 = 49²-d² , d² = 1 , d = ±1
the nubers are ( 6,7 ,8) or (8,7,6)
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