if three numbers are in AP whose sum is 32 and product is 729. then the smallest number from this number
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Step-by-step explanation:
Hi,
Let (a - d), a, (a +d) are three numbers are in A. P
sum of the terms = 33
a-d + a + a + d = 33
3a = 33
a=11
product of the terms = 792
(a - b) ×ax (a+d) = 792
a (a2 - d2) = 792
11 ( (11)^2 - d² ) = 792
121 - d2 = 792/11
121 - d2 = 72
- d2 = 72 - 121
-d2 = -49
d2=49
d=+7,-7
Therefore,
Three numbers are ,
a - d = 11 - 7 = 4,
a = 11,
a + d = 11 + 7 = 18
Required smallest number = 4
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