Question

If three numbers are in the ratio of 2 :3:5 and their H.C.F. is 8, what is the sum of those three numbers?

Answer 1

Here given that H.C.F. is 8.

So the number be 16,24,40.

And sum is(16+24+40)=80

Answer 2

Answer: The sum of the three numbers is 80.

Step-by-step explanation: Let the three given numbers be a, b and c. Since the ratio of these three numbers is 2:3:5, so we can write

a = 2x, b = 3x and c = 5x.

Therefore, HCF (a, b, c) = HCF (2x, 3x, 5x) = x. And given that HCF is 8.

So, x=8, and we get

a = 2×8 = 16, b = 3×8 = 24  and c = 5×8 = 40.

∴ The sum of the three numbers = a+b+c = 16+24+40 = 80.

Thus, the answer is 80.