If three particles of mass 2 kg 1 kg and 3 kg are placed at corners of an equilateral triangle of perimeter 6 metre
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Explanation:
Let the trangle ABC is placed in such a way in the co ord plane so that the mid point of the side BC is the origin.
point A=1kg point B=2kg point C=3kg hence the X co ord is=[(2×(-1/2)+(3×1/2)+(1×0)]/(2+3+1)=1/12.
The Y co ord is=[(2×0)+(3×0)+(1×√3/2)]/(1+2+3)=√3/12 .
Hence the COM is At=( 1/12 , √3/12)
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