Math, asked by kingsattu007, 4 months ago

if three pipes P, Q and R can empty full tank in 25 minutes, if P is twice as efficient as Q and Q is twice as efficient as R then in how much time R will empty 60% of the tank?​

Answers

Answered by sakapatel
0

Step-by-step explanation:

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

A.

4

1

2

hours B.

1

13

17

hours

C.

3

9

17

hours D.

2

8

11

hours

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2. Two pipes A and B can fill a cistern in

37

1

2

minutes and

45

minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if pipe B is turned off after

A. 5 min B. 9 min

C. 15 min D. 10 min

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3. A pump can fill a tank with water in 2 hours. Because of a leak, it took

2

2

3

hours to fill the tank. The leak can drain all the water of the tank in

A. 9 hours B. 8 hours

C. 10 hours D. 6 hours

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