If three points (k,2k),(2k,3k),(3,1) are collinear, then k is equal to:
Answers
Answered by
0
I hope that you got your required answer
Answered by
2
Step-by-step explanation:
[ k 2k 1 ]
[ 2k 3k 1 ] = 0
[ 3 1 1 ]
=> k (3k-1) -2k(2k-3) + 1(2k-9k) = 0
=> 3k² - k - 4k² + 6k - 7k = 0
=> -k² - 2k = 0
k² + 2k = 0
k(k+2) = 0
k = 0 , -2
Similar questions