If three positive real numbers a,b,c are in AP such that abc=4, then the minimum value of b is
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Answered by
0
Answer:
We know, from AM≥GM, for positive quantities, that
3
(a+b+c)
≥
3
abc
3
(a+c)+b
≥
3
abc
But 2b=(a+c).
This implies
3
3b
≥(4)
1/3
b≥(2)
2/3
Answered by
0
Answer:
.
Step-by-step explanation:
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