If three register are connected in parllel its over all restiance 0.5ohm then callculate the value of x.
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Answer:
1/R=1/3+1/4+1/12
=4+3+1/12
=8/12
=2/3
R=3/2
=1.5ohm
I=V/R
=6/2
=3 amp
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