Question

If three resistance 10, ,5,15,ohm are connected in series with a potential of 20v. Then what will be the equivalent resistance? Also calculate current through the circuit?

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{R_{equivalent}=30\Omega}}}$

$\green{\tt{\therefore{Current\:flow=\frac{2}{3}\:A}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Resistance = 10 \Omega \: 5\Omega \: and \: 15\Omega \: in \: series \\ \\ \tt: \implies Potential \: difference(V) = 20 \: V \\ \\ \red{\underline \bold{To \: Find:}}\\ \tt : \implies R_{equivalent} = ? \\ \\ \tt: \implies Current \: flow(I) = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies R_{equivalent} = R_{1} + R_{2} + R_{3} \\ \\ \tt: \implies R_{equivalent} = 10 + 5 + 15 \\ \\ \green{\tt: \implies R_{equivalent} = 30 \Omega} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies V = IR \\ \\ \tt: \implies 20 =I \times 30 \\ \\ \tt: \implies \frac{20}{30} = I \\ \\ \green{\tt: \implies I = \frac{2}{3}\:A}$

Answer 2

Given

Three resistors $10{\Omega}\:5\:{\Omega}\:15{\Omega}$

Potential difference = 20v

To find

Current

Solution

Here,the circuit is connected in series

Therefore,

$\boxed{\boxed{\sf\red{R_{equ}=R_1+R_2+R_3 }}}$

Putting the Values of Resistors

$\implies\:R_{equ}=10{\Omega}+5{\Omega}+15{\Omega}$

$\implies\:R_{equ}=30{\Omega}$

From ohm's law

$\boxed{\boxed{\sf\red{V=IR }}}$

$\implies\:20=i30{\Omega}$

$\because\:I=\frac{2}{3}A$

Hence,I =2/3