Question

If three resistances of 25 ohm, 20 ohm, and 15 ohm are connected in series then the equivalent resistance will be……….​

Answer 1

☯ Equivalent resistance = 60 Ω

• R₁ [ Resistor 1 ] = 25 Ω
• R₂ [ Resistor 2 ] = 20 Ω
• R₃ [ Resistor 3 ] = 15 Ω

____________________

As we know that ,

Equivalent resistance when connected in series :-

♦ Equivalent resistance = R₁ + R₂ + R₃ .... Rn

⇒ Equivalent resistance = ( 25 + 20 + 15 )Ω

⇒ Equivalent resistance = ( 35 + 25 ) Ω

⇒ Equivalent resistance = 60 Ω

☯ Learn More !

Equivalent resistance when connected in parallel :-

♦ Equivalent resistance = 1/R₁ + 1/R₂ + 1/R₃ ...1/Rn

Answer 2

$\huge \mathfrak {Given}$

Three resistor of 25Ω,20Ω and 15Ω

$\huge \mathfrak{Need\: To \:Find}$

Equivalent resistance

$\huge \mathfrak {Solution}$

Here, the resistor are connected in parallel series

So,

$\sf R_n = R1 + R2 + R3$

$\sf R_n = 25 \Omega + 20 \Omega + 15 \Omega$

$\sf \blue{R_n = 60 \Omega}$

Note : If you will watch the answer from web (\Omega) will be shown as Ω

More Info :-

When resistor are added into a parallel

then we use :-

Rⁿ = 1/R1 + 1/R2 + 1/R3... 1/Rⁿ

Where

R1 is the First Resistor

R2 is the second Resistor

R3 is the Third Resistor