If three resisters R1=2ohm and R2=5ohm and R3=1ohm are connected in series then the equivalent resisitance will be (a)11ohm (b)8ohm(c)10ohm (d)12ohm
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R=R1+R2+R3
so, R=2+5+1=8
therefore, b)8 ohm
Answered by
0
Equivalent resistance , R = R1 + R2 + R3
R = 2 + 5 + 1
R = 8 ohm
Hence , The correct answer is (b) 8 ohm
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