If three resistor 2ohm,4ohm and 6ohm are connected in parallel in a circuit calculate the equivalent resistance of the combination
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Answer:
R1=2ohm
R2=4ohm
R3=6ohm
So,
1/R = 1/R1 + 1/R2 + 1/R3
R = R1R2R3/R1+R2+R3
R = 2×4×6/2+4+6 ohm
R = 48/12 ohm
R = 4 ohm
Hope it helped!!
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