Question

If three resistor of 6ohm ,9ohm and 21 ohm are connected in series to a 12 volt battery find the potential difference across the 21 ohm resistor

Answer 1

Answer:

7

Explanation:

v1=V×r1/(r1+r2+r2)

v1=12×21/36

v1=7

Answer 2

The potential difference across the 21 ohm resistor is 7.14 volts.

Explanation:

Given that,

Resistor 1, $R_1=6\ \Omega$

Resistor 2, $R_2=9\ \Omega$

Resistor 3, $R_3=21\ \Omega$

All three resistors are connected in series to a 12 volt battery. In this case, the current in all resistors is same. The equivalent resistance is given by :

$R=R_1+R_2+R_3$

$R=6+9+21$

$R=36\ \Omega$

Let I is the current flowing in the circuit. So,

$I=\dfrac{V}{R}$

$I=\dfrac{12}{36}=0.34\ A$

Now the potential difference across the 21 ohm resistor is given by :

$V=IR_3$

$V=0.34\ A\times 21$

V = 7.14 volts

So, the potential difference across the 21 ohm resistor is 7.14 volts.

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