Physics, asked by ravi66662, 11 months ago

. If three resistors of 6Ω, 9Ω and 21Ω are connected in series to a 12V battery, find

Answers

Answered by ABHAYSIRISHBR

5

Answer:

Current = 0.3A

Explanation:

in series 6+9+21=36ohm I =v/r 12/36=.33

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