Question

if three resistors of resistances 2ohm, 4ohm,6ohm are connected in series with a 6V battery then what is the current following through the resistors ​

Answer 1

Answer:

0.5 ampere

Explanation:

here

R1=2ohm

R2=4ohm

R3=6ohm

voltage given =6V

since resisters are connected in series

R(total)=R1+R2+R3

            =2+4+6=12

as

V=IR

6=Ix12

I=6/12=0.5A