if three sides of a triangle in length are represented by three consecutive odd numbers and the perimeter is 75 cm find the length of the sides
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let one side be x
these are consecutive odd numbers.
therefore,
other side = x+2
third side = x+4
perimeter=75 cm
perimeter of a triangle=side+side+side
75=(x)+(x+2)+(x+4)
75=x+x+2+x+4
75=3x+6
75-6=3x
69=3x
x=69/3
x=23
therefore,
length of first side = x=23 cm
second side=x+2=23+2=25 cm
third side=x+4=23+4=27 cm
these are consecutive odd numbers.
therefore,
other side = x+2
third side = x+4
perimeter=75 cm
perimeter of a triangle=side+side+side
75=(x)+(x+2)+(x+4)
75=x+x+2+x+4
75=3x+6
75-6=3x
69=3x
x=69/3
x=23
therefore,
length of first side = x=23 cm
second side=x+2=23+2=25 cm
third side=x+4=23+4=27 cm
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