if three straight lines are drawn on a white board at random with the eyes closed. show that the probability of a forming a triangle is 1/7
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1/7
Step-by-step explanation:
There are 7 possible cases.
Case1 -> The 3 lines coincide each other
Case2 -> The 3 lines pass through a same point i.e. they are concurrent lines
Case 3 -> All 3 lines are parallel to each other.
Case4 -> Line 1 and Line 2 are parallel and Line 3 is not parallel to any of them
Case5 -> Line 2 and Line 3 are parallel but Line 1 is not parallel to any of them
Case6 -> Line 1 and Line 3 are parallel but Line 3 is not parallel to any of them
Case 7->The 3 lines form a triangle
Here, no. of favorable outcome=1
No. of possible outcomes=7
:. The required probability is 1/7
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