Question

If three taps are open together, a tank is filled in 10 h. one of the taps can fill in 5 h and another in 10 h. at what rate does the 3rd pipe work?

Answer 1

I think that time taken by second tap is wrong
Can u please check it once again

Answer 2

Answer:

5 hours

Step-by-step explanation:

Let x be the no. of hours for 3rd pipe to fill the tank alone

So, 1 hour work of 3rd pipe = $\frac{1}{x}$

One of the taps can fill in 5 h

1 hour work of Tap 1 = $\frac{1}{5}$

Second tap can fill in 10 hours

1 hour work of second tap = $\frac{1}{10}$

1 hour work if they work together = $\frac{1}{x}+\frac{1}{5}+\frac{1}{10}$

We are also given that If three taps are open together, a tank is filled in 10 h

So, 1 hour work together = $\frac{1}{10}$

So,  $\frac{1}{x}+\frac{1}{5}+\frac{1}{10}=\frac{1}{10}$

$\frac{1}{x}=\frac{-1}{5}$

So, x = -5

So, negative shows that Third pipe is removing the water from the tank

So, 3rd pipe can complete work alone in 5 hours