if three unbiased coins are to see what is the probability of getting,1 head,2 head,atlist 2head, at most 1 head
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Step-by-step explanation:
if three unbiased coins are to see what is the probability of getting,1 head,2 head,atlist 2head, at most 1 head
Answered by
1
Step-by-step explanation:
A-probability of getting 1 head
n(s)=8
n(A)=3
p(A)=n(A)/n(s)
=3/8
B-probability of getting 2 heads
n(B)=3
p(B)=n(B)/n(s)
3/8
C-probability of getting atleast 2 head
n(C)=4
p(C)=n(C)/n(s)
=4/8=1/2
D-probability of getting atmost one head
n(D)=4
p(D)=n(D)/n(s)
= 4/8=1/2
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