Question

If three unbiased coins are tossed together find the probability of getting at most two heads

Answer 1

Answer:

Step-by-step explanation:

The space events are

(H,H,H) (T,T,T) (T,H,T) (T,T,H) (H,T,T) (H,T,H) (H,H,T) (T,H,H)

So number of outcomes- 8

P(event) = number of favourable outcomes/ total number of outcomes

At most 2 heads means there shouldn’t be more than 2 heads...

This includes outcomes containing no heads or one head.

P(at most 2 heads) = 7/8

(H,H,H) cannot be counted as there are 3 heads...

Answer 2

Total no. of outcomes or we can say that we will first draw a sample space, which will be as follows. (HHH, HHT, HTH, THH, TTT, TTH, THT, HTT)

n(s)=8

P(getting 2 heads)= favourable outcomes / total no. of outcomes = 4/8 = 1/2

Or we can also describe it by saying that getting two heads (here at least two heads) have 50% chances