Question

If threee resistor are in pparralel connection 2, 3 6, the net resistance?. ​

Answer 1

Answer:

Net resistance will be

1/r =1/2 + 1/3 + 1/6

1/r= 6/6

r = 1

Answer 2

$\;\;\underline{\textbf{\textsf{Gɪᴠᴇɴ :-}}}$

•R₁= 2Ω

•R₂ = 3Ω

•R₃ = 6Ω

$\;\;\underline{\textbf{\textsf{ Tᴏ Fɪɴᴅ :-}}}$

• Net resistance

$\;\;\underline{\textbf{\textsf{Sᴏʟᴜᴛɪᴏɴ :-}}}$

Parallel Combination :-

$\bf \dagger \: \: \: \: \: \dfrac{1}{R_p}= \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} ... \dfrac{1}{R_n}$

$\tt \dashrightarrow \: \: \dfrac{1}{R_p}= \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{6}$

$\tt \dashrightarrow \: \: \dfrac{1}{R_p}= \dfrac{3 + 2 + 1}{6}$

$\tt \dashrightarrow \: \: \dfrac{1}{R_p}= \dfrac{ \cancel6}{ \cancel6}$

$\tt \dashrightarrow \: \: \dfrac{1}{R_p}= 1\Omega.$

$\dashrightarrow {\boxed{\frak{\purple{ \bf R_p= 1\Omega}}}}$

ㅤ$\;\;\underline{\textbf{\textsf{Hence -}}}$

$\underline{\textsf{ Net resistance will be </p><p>\textbf{ 1 Ω}}}.$

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