Chemistry, asked by amit761, 1 year ago

If threshold wavelength (aº) for ejection of electron
from metal is 330 nm, then work function for the
photoelectric emission is
(1) 6 × 10-10 j (2) 1.2 x 10-18 J
(3) 3 × 10-19 J (4) 6 x 10-19 J​

Answers

Answered by YameshPant
9

Answer:

work function=Eo=hυO=hc/λo

=6.626*10-³⁴*3*10^8/330*10^-9

=(6.626*10-³⁴*10^18)/11

=0.6023*10^-16

=6*10^-17J

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