If threshold wavelength for ejection of electron from metal is 330nm, then work function for photoelectric emission is Work function is the minimum energy required to eject an electron from the metal surface.
Answers
Answered by
0
Explanation:
If threshold wavelength (lambda_(0)) for ejection of electron fr. Solution : Work function is `hv_(0) = (hc)/(lambda_(0))` <br> `= (6.62 xx 10^(-34) xx 3 xx 10^(8))/(330 xx 10^(-9)) = 6 xx 10^(-19)J`.
Answered by
1
Answer:
Work function is the minimum energy required to eject an electron from the metal surface.
work function=hv°
Threshold frequency=c/^=3×10^8/330×10^-9=1×10^17/11=8^-1
work function=6.626×10^-34×10^17/11=6×10^-19J
Explanation:
Similar questions
Math,
2 months ago
Chinese,
2 months ago
Social Sciences,
5 months ago
English,
5 months ago
Computer Science,
10 months ago
Computer Science,
10 months ago