Chemistry, asked by Anonymous, 7 months ago

If threshold wavelength for ejection of electron from metal is 330nm, then work function for photoelectric emission is Work function is the minimum energy required to eject an electron from the metal surface.

Answers

Answered by sunakat483
0

Explanation:

If threshold wavelength (lambda_(0)) for ejection of electron fr. Solution : Work function is `hv_(0) = (hc)/(lambda_(0))` <br> `= (6.62 xx 10^(-34) xx 3 xx 10^(8))/(330 xx 10^(-9)) = 6 xx 10^(-19)J`.

Answered by Anonymous
1

Answer:

Work function is the minimum energy required to eject an electron from the metal surface.

work function=hv°

Threshold frequency=c/^=3×10^8/330×10^-9=1×10^17/11=8^-1

work function=6.626×10^-34×10^17/11=6×10^-19J

Explanation:

Similar questions