If thrice angle A= 4 times angle B= 6 times angle C then find angle ABC
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let A be x
let B be y
let C be z
3x=4y=6z
x+y+z=180
y=3/4x
z=3/6x
So,
x + 3/4x + 3/6x = 180
12x/12 + 9x/12 + 6x/12 = 180
27x/12 = 180
27x = 180×12
x = 180/27 ×12
x = 80
y = 3/4x = 3/4×80 = 60
z = 3/6x = 3/6×80 = 40
let B be y
let C be z
3x=4y=6z
x+y+z=180
y=3/4x
z=3/6x
So,
x + 3/4x + 3/6x = 180
12x/12 + 9x/12 + 6x/12 = 180
27x/12 = 180
27x = 180×12
x = 180/27 ×12
x = 80
y = 3/4x = 3/4×80 = 60
z = 3/6x = 3/6×80 = 40
chiku1818:
Thank you bro
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