Question

If thrice of a's age 6 years ago be subtracted from twice the present age, the result would be equal to his present age. find a's present age. 1)62)93)124)15

Answer 1

Option (B) - 9.

Let the age of A be x.

Before 6 years: x - 6.

Given thrice of age 6 years ago be subtracted from twice the present's age.

2x - 3(x-6) = x

2x - 3x - 18 = x

18 = 2x

x = 9.

Answer 2

Answer:

9 years

Step-by-step explanation:

Let the present age of a be x

a's Age 6 years = x-6

Since we are given that thrice of a's age 6 years ago be subtracted from twice the present age, the result would be equal to his present age.

So, thrice of a's age 6 years ago= 3(x-6)

Twice of present age = 2x

So, A.T.Q

$2x-3(x-6)=x$

$2x-3x+18=x$

$18=x+x$

$18=2x$

$x=9$

Hence the present age of a is 9 years