Question

If time taken by a body to reach at maximum height is 10 sec. How can we find speed at the time of projection from ground using above context? g=10 m/s2​

Answer 1

Answer:

Using 1st equation of motion,

v=u+at

Final velocity of the body is zero, i.e. v=0

Acceleration a=−g=−9.8 m/s

2

So, 0=u−gt

⇒u=gt...(i)

Now let us consider 2nd equation of motion,

s=ut+

2

1

at

2

Height reached =10 m

Using (i), we get

⇒10=(gt)t−

2

1

gt

2

⇒10=

2

1

gt

2

⇒t=

g

10×2

⇒t=

9.8

10×2

⇒t=

2.0408

⇒t=1.428≈1.43sec

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