Question

If tita=30° , verify
that cos
2tita 1-tansqare tita /1- tan²tita​

Answer 1

Answer:

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Answer 2

$\huge\fbox{Solution:-}$

The given equation is :

$\bf{tan}$Ф= $\bold\red\frac{2tan}{1-tan^{2} }$

Now, ifФ=30° , then the equation becomes,

$\bf{tan2}$ (30°)= $\bf\frac{2tan30^{°} }{1-tan^{2}30^{°} }$

tan60° = $\bf\frac{2×\sqrt[1]{3} }{1-\frac{1}{3} }$

$\bf{\sqrt{3}$       = $\frac{\sqrt[2]{3} }{\frac{2}{3} }$

$\bf\sqrt{3}$       = $\sqrt{3}$

 Hence proved.