if tn= 2 + 3n, then find the sum of first 7 term of AP
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Heya !!!
Tn = 2 + 3N
T1 = 2 + 3 × 1
=> 2 + 3
=> 5
And,
T2 = 2 + 3 × 2
=> 2 + 6
=> 8
T3 = 2 + 3 × 3
=> 2 + 9
=> 11
AP= 5 , 8 , 11 ......
Here,
First term ( A) = 5
Common Difference (D) = 8-5 = 3
Sn = N/2 × [ 2A + ( N-1) × D ]
S7 = 7/2 × [ 2 × 5 + ( 7-1) × 3 ]
=> 7/2 × ( 10 + 18)
=> 7/2 × 28
=> 7 × 14
=> 98
HOPE IT WILL HELP YOU...... :-)
Tn = 2 + 3N
T1 = 2 + 3 × 1
=> 2 + 3
=> 5
And,
T2 = 2 + 3 × 2
=> 2 + 6
=> 8
T3 = 2 + 3 × 3
=> 2 + 9
=> 11
AP= 5 , 8 , 11 ......
Here,
First term ( A) = 5
Common Difference (D) = 8-5 = 3
Sn = N/2 × [ 2A + ( N-1) × D ]
S7 = 7/2 × [ 2 × 5 + ( 7-1) × 3 ]
=> 7/2 × ( 10 + 18)
=> 7/2 × 28
=> 7 × 14
=> 98
HOPE IT WILL HELP YOU...... :-)
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