Question

If tn=(2n-1) for an A.P. 1,3,5,7,......(2n-1);then find 30th term of A.P. .

Answer 1

Answer:

t30= a+29d

so ,

t30=1+29×2=58

Answer 2

The 30th term in the A.P. 1,3,5,7,......(2n-1) is 59.

• This can be calculated in the ways given below:

• As per the question, the nth term in the given A.P. is tn = (2n-1)

• Thus, for the 30th term, n =30.

• Putting the value of n in the term tn, we get,

        tn = (2n - 1)

        t(30) = (2 x 30 - 1)

                 = (60 - 1)

                 = 59

• Thus, the 30th term is 59.