If tn=2n-5 is the nth term of an A.P., then find its first five terms.
Answers
Answered by
27
Answer:
if tn=2n-5
t(1)=2(1)-5
tn=-3
t(2)=2(2)-5
tn=-1
t(3)=2(3)-5
tn=1
t(4)=2(4)-5
tn=3
t(5)=2(5)-5
tn=5
Answered by
11
Answer:
The First Five terms are -3, -1, 1, 3, 5.
Step-by-step explanation:
tn = 2n-5
when n = 1
t1 = 2(1) - 5 = 2 - 5 = -3.
when n = 2
t2 = 2(2) - 5 = 4 - 5 = -1.
when n = 3
t3 = 2(3) - 5 = 6 - 5 = 1.
when n = 4
t4 = 2(4) - 5 = 8 - 5 = 3.
when n = 5
t5 = 2(5) - 5 = 10 - 5 = 5.
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