if TN =2n+n,then find sn
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Answer:
Tn=2n+n
T1=a=2+1=3
T2=2(2)+2=4+2=6
a=3
d=3
Sn=ⁿ/2(2a+(n-1)d)=ⁿ/2(6+3n-3)=(3n²+3n)/2
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