if Tn=5n-2,then find S4
Answers
Answered by
5
Answer:
Step-by-step explanation:
Given that nth term of an Arithmetic progression,
tn = (5n - 2)
So, the first term,
t1 = (5 × 1) - 2
= 5 - 2
= 3
and
the second term,
t2 = (5 × 2) - 2
= 10 - 2
= 8
Hence, the common difference,
d = t2 - t1
= 8 - 3
= 5
∴ the 19th term of the Arithmetic progression,
t19
= t1 + (19 - 1)d
= 3 + (18 × 5)
= 3 + 90
= 93
#MarkAsBrainliest
Answered by
12
Answer:
T1=3
T2=8
T3=13
3+8+13+..........is in A. P
a=3,d=5
S4=4/2[6+3(5)]=42
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