Question

if Tn=5n-2,then find S4​

Answer 1

Answer:

Step-by-step explanation:

Given that nth term of an Arithmetic progression,

tn = (5n - 2)

So, the first term,

t1 = (5 × 1) - 2

= 5 - 2

= 3

and

the second term,

t2 = (5 × 2) - 2

= 10 - 2

= 8

Hence, the common difference,

d = t2 - t1

= 8 - 3

= 5

∴ the 19th term of the Arithmetic progression,

t19

= t1 + (19 - 1)d

= 3 + (18 × 5)

= 3 + 90

= 93

#MarkAsBrainliest

Answer 2

Answer:

T1=3

T2=8

T3=13

3+8+13+..........is in A. P

a=3,d=5

S4=4/2[6+3(5)]=42