Question

If tn = 6n + 5, then find tn+1
(Arithmetic progression)

Answer 1

tn=6n+5 (given)

let n=1 then 6 (1)+5=11, tn+1=11+1=12
n=2 then 6 (2)+5=17, tn+1=17+1=18
n=3 then 6(3)+5=23,tn+1=23+1=24
n=4 then 6 (4)+5=29,tn+1=29+1=30

so clearly for consecutive values of n we get different values
Also We saw that the by putting different values of n we get a series which is an A.P.

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Answer 2

Answer:

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