If tn be the nth term of an A.P Such that t4/t7= 2/3 find t8/t9
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Answered by
16
We know that,
t4 = a + 3d
t7 = a + 6d
Given,
a + 3d / a + 6d = 2/3
3 ( a + 3d ) = 2 ( a + 6d )
3a + 9d = 2a + 12d
a = 3d .
Now,
t8 = a + 7d = 3d + 7d = 10d
t9 = a + 8d = 3d + 8d = 11d
t8/t9 = 10d/11d = 10/11
t4 = a + 3d
t7 = a + 6d
Given,
a + 3d / a + 6d = 2/3
3 ( a + 3d ) = 2 ( a + 6d )
3a + 9d = 2a + 12d
a = 3d .
Now,
t8 = a + 7d = 3d + 7d = 10d
t9 = a + 8d = 3d + 8d = 11d
t8/t9 = 10d/11d = 10/11
Answered by
9
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Good evening
Your answer is given in the attachment
I hope it will help you
Thanks
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