Question

If tn is the nth term of an a.p then t2n.tn is

Answer 1

$t_{n}.t_{2n}=[a+(n-1)d][a+(2n-1)d]$

Step-by-step explanation:

Given,

The nth term of an AP $=t_{n}$

To find, the value of $t_{2n}.t_{n}=?$

Let first term of an AP = a and common difference of an AP = d

We know that,

The nth term of an AP,

$t_{n}=a+(n-1)d$

The 2nth term of an AP,

$t_{2n}=a+(2n-1)d$

∴ $t_{n}.t_{2n}=[a+(n-1)d][a+(2n-1)d]$

Hence, $t_{n}.t_{2n}=[a+(n-1)d][a+(2n-1)d]$

Answer 2

Answer:

if tn is the nth term of a.p then t2n - tn is