If tn=(n-1) (n-2) (n-3) then what is the is the third term
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It's simple :
The condition is given that, tn = (n-1) (n-2) (n-3)
We have to find t3
so, put n=3 in given condition
Therefore,
t3 = (3-1) (3-2) (3-3)
= 2 × 1 × 0
= 0
HENCE, THIRD TERM (t3) = 0
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