Question

If to men walking opposite to each other from two towns distance of 10 after the walk after 80 minutes the distance between them is 2 kilometre if the speed of man of 3 km per hour find the speed of other man

Answer 1

Distance between two men = 10 km
After 80 mins.
Distance between them is = 2 km
The first men's speed = 3 km/h= 3/60 km/min
in 80 min he walks,
3/60 × 80= 4km
distance between them after 80 min is 2 km
means
Second men walks
10-(4+2)km=4km in 80 min
means second men's speed is 4km/80min= 1/20 km/min = 60/20 km/hr= 3km/h.
which is same speed as the first men's speed

Answer 2

Distance between them=10kms
After 80 mins of walk distance between them=2km
Speed of the first man=3kmph
80mins=1.20hours
per hour =3kms per 20mins=3/3=1kms
so the first man walks 3+1=4kms in 80 mins
Given that the two men were walking in opposite direction
The distance reduced between them=walk of 1st person + walk of second person
10-2=4+x
8=4+x
8-4=x
x=4
Distance covered by second person=4kms
As the two persons covers same distance their speed is also equal
So second person speed =3kmph