Question

If ton 2A=cot(A-18°) where 2A is on actual angle then prove that A=36°​

Answer 1

Step-by-step explanation:

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Answer 2

tan2A = cot(A-18°)

• ⇒ cot(90°-A) = tan A

⇒ cot(90° - 2A) = cot(A-18°)

• cot gets cancelled

⇒ 90 - 2A = A - 18

⇒ 90° + 18° = A + 2A

⇒ 3A = 108°

⇒ A = 108/3 = 36°

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