if total surfaces area of a cube is 1014sq. cm, find the lateral surface area and manin diagonal of the cube.
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We know that total surface area of cube = 6a^2
So 6a^2 = 1014 cm^2
a^2 = 1014/6 = 169 cm^2
a = √169 = 13 cm
Thus length of cube is 13 cm.
Lateral surface area = 4a^2 = 4×13^2 = 676 cm^2
Main diagonal = √3 a = √3×13 = 13√3 cm
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We know that Total surface area of a cube = 6a^2
given T.S.A of cube is =1014 sq cm
6a^2 = 1014
a^2 = 1014/6
a^2 = 169
a^2 = 13^2
a=13 cm
Lateral surface area of cube is = 4a^2
= 4× 13×13
= 676sqcm
given T.S.A of cube is =1014 sq cm
6a^2 = 1014
a^2 = 1014/6
a^2 = 169
a^2 = 13^2
a=13 cm
Lateral surface area of cube is = 4a^2
= 4× 13×13
= 676sqcm
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