Question

if tp and tq are tangents to a circle with centre O, so that POQ = 110° ,then PTO is​

Answer 1

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Given, ∠POQ=110
∘

We know,
∠OPT=∠OQT=90
∘
(Angle between the tangent and the radial line at the point of intersection of the tangent at the circle)
Now, in quadrilateral POQT
Sum of angles=360
∠OPT+∠OQT+∠PTQ+∠POQ=360

90+90+∠PTQ+110=360
∠PTQ=360−290
∠PTQ=70