Question

if TP and TQ are the two tangents to a circle with Centre O such that angle PTQ= 47 degree then find angle POQ​

Answer 1

Step-by-step explanation:

Given, ∠POQ=110

∘

We know,

∠OPT=∠OQT=90

(Angle between the tangent and the radial line at the point of intersection of the tangent at the circle)

Now, in quadrilateral POQT

Sum of angles=360

∠OPT+∠OQT+∠PTQ+∠POQ=360

∘

90+90+∠PTQ+110=360

∠PTQ=360−290

∠PTQ=70°