If TP and TQ are the two tangents to a circle with
centre O, such that ∠PTQ = 47°, then find
∠POQ.
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Answer:
Thus ∠POQ=133°
Step-by-step explanation:
in the fig PT and QT are tangents and O is the centre
Now in the quadrilateral POQT
∠P=∠Q= 90
Thus ∠P+∠Q+∠POQ+∠PTQ=360
90+90+x+47=360
x=360-180-47=133
x=133
Thus ∠POQ=133°
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