Math, asked by indianosr, 6 months ago

If TP and TQ are the two tangents to a circle with

centre O, such that ∠PTQ = 47°, then find

∠POQ.​

Answers

Answered by Anonymous
7

Answer:

Thus ∠POQ=133°

Step-by-step explanation:

in the fig PT and QT are tangents and O is the centre

Now in the quadrilateral POQT

∠P=∠Q= 90

Thus ∠P+∠Q+∠POQ+∠PTQ=360

90+90+x+47=360

x=360-180-47=133

x=133

Thus ∠POQ=133°

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