Math, asked by vishalnivesh, 7 months ago

If TP and TQ are the two targets to a circle with centre O, so that POQ=110, then PTQ is equal to

Answers

Answered by son36

2

Answer:

70°

Step-by-step explanation:

TPQ +TQP+ POQ+ PTQ =360°

90°+90°+110°+TPQ=360°

TPQ+290°=360°

TPQ=360°-290°

TPQ=70°

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