If tp and tq are two tangents to a circle with centre o so thatthat poq = 110, then, ptq is equal to? Merit nation
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Answer: 70°
Step-by-step explanation:
Op is perpendicular to TP. (Radius is perpendicular to the tengant)
Similarly OQ is perpendicular to TQ.
So angle TQO and TPO are 90°
So by using A.S.P in quad. TPOQ
angle TPO + angle POQ + angle OQT + angle QTP = 360°
90° + 110° + 90° + angle QTP = 360°
So, angle QTP = 70°
HOPE YOU WILL UNDERSTAND....
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