If TP and TQ are two tangents to a circle with centre O, so that ÐPOQ = 100° then ÐPTQ is equal to (A) 100° (B) 50° (C) 60° (D) 200°
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Answered by
4
Answer:
Step-by-step explanation:
angle sum property of a quadrilateral,
∠t + ∠p + ∠ q + ∠o = 360°
90° + 90° + 100° + ∠o = 360°
∠o = 360° - 280°
∴∠o = 80°
your options are wrong!!!!
Answered by
1
ans = 80
but this is not available in options please consider
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