If triangl PQR is similar to triangle XYZ, angel Q=50 degree and angel R=70 degree ,then angel X +angel Y is equal to
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Answer:
angle Q=50
angleR=70
then angle P=60 by angle sum property
Step-by-step explanation:
by AAS PROPERTY BOTH THE TRIANGLE =
angle Q=angle Y
angle P=angle X
X+Y=50+60
=110°.
Answered by
2
In ∆ PQR and ∆ XYZ ,
PQ = XY ,
QR = YZ ,
RP = ZX,
By SSS Congruence ,
∆ PQR =~ ∆ XYZ
By CPCT ,
< Q = < Y
50° = <Y
<R = <Y
70° = <Y
In ∆PQR ,
< P + < Q + < R = 180°
< P = 60° = < X
< X + <Y = 60° + 50°
= 110°
PQ = XY ,
QR = YZ ,
RP = ZX,
By SSS Congruence ,
∆ PQR =~ ∆ XYZ
By CPCT ,
< Q = < Y
50° = <Y
<R = <Y
70° = <Y
In ∆PQR ,
< P + < Q + < R = 180°
< P = 60° = < X
< X + <Y = 60° + 50°
= 110°
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