Question

If triangle ABC, a=10, b=14, c=18 find the value of Cos A/2 or Sin A/2​

Answer 1

Answer:

Step-by-step explanation:

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Assume AC is the 14cm base of the triangle, and B is the opposite vertex.

Drop a perpendicular from B to point D on the base AC.

Using Pythagoras on the triangles ABD and BCD, we can solve for AD, BD and DC.

We get AD = 9cm, BD = 12cm and DC = 5cm.

Therefore Sin A = 12/15 = 0.8

Thus Sin (A/2) = 0.447

Answer 2

Answer:

Step-by-step explanation:

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