if triangle abc, ab=ac, bc. is produced to d such that angle ACD=100°, then angle A is?
1.20°
2.40°
3.60°
4.80°
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➨We have ,
→ ZACD + ZACB = 180 ° [ Linear Pair ]
→ 100 ° + ZACB = 180 °
→ ZACB = 180 ° - 100 °
→ ZACB = 80 °
➨From ( i ) & ( ii ) ,
➨ We get
➨ Angle ZABC = Angle ZACB = 80 °
➨Now ,
→ ZABC + ZACB + ZA = 180º .... [ Sum of the 3 interior angles of a triangle is 180° ]
→ Substituting the values of ZABC & ZACB ,
➨ We get
→ 80 ° + 80 ° + A = 180 °
→ 160 ° + ZA = 180 °
→ ZA = 180 ° - 160 °
→ ZA = 20 °
Thus , the measure of Angle ‘A’ is 20 °
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