Question

if triangle abc, AC = 25 CM, BC = 7 CM, AB = 24 CM then cosec a =

Answer 1

Answer:

thanks

Step-by-step explanation:

for free points

Answer 2

Answer:

In Δ ABC, right-angled at B

Using Pythagoras theorem

AC² = AB² +BC²

AC² = 576 + 49 = 625

AC = √635

AC = ±25

AC\:=\:+ 25AC=+25

Now

(i) In a right angle triangle ABC where B=90° ,

Sin A = \frac{BC}{AC}

AC

BC

= \frac{7}{25}

25

7

CosA = \frac{AB}{AC}

AC

AB

= \frac{24}{25}

25

24

(ii) Sin C = \frac{AB}{AC}

AC

AB

= \frac{24}{25}

25

24

Cos C = \frac{BC}{AC}

AC

BC

= \frac{7}{25}

25

7