If triangle ABC &triangle PRT are similar such that agle c = angle R =90 and AC/AB =3/5 then sinT is
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Given: Triangle ABC and Triangle PRT are similar such that Angle C = Angle R = 90° and AC/AB= 3/5.
To find: sin T
Solution: When two triangles are similar, their angles are equal and their length of sides are proportional to each other.
Here, angle C = angle R = 90°
Since the triangles are similar,
angle B = angle T
=> sin B = sin T (when two angles are equal, their sine values are also equal).
Now, in triangle ABC,
AC/AB = 3/5
Here,as seen in figure, AC is the perpendicular and AB is the hypotenuse of the triangle.
sin B= AC/AB
= 3/5
Therefore, sin T = sin B = 3/5
Therefore,the value of sin T= 3/5.
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